Articulo de referencia

2017 Indian Open

The 2017 Indian Open was a professional ranking snooker tournament that took place between 12 and 16 September 2017 in Vishakhapatnam , India . [ 1 ] It was the fourth ranking e...

The 2017 Indian Open was a professional rankingsnooker tournament that took place between 12 and 16 September 2017 in Vishakhapatnam, India.[1] It was the fourth ranking event of the 2017/2018 season.

Qualifying took place between 1 and 2 August 2017 in Preston, England.

Anthony McGill was the defending champion, having beaten Kyren Wilson 5–2 in the 2016 final. McGill reached the final again but was beaten by John Higgins, who won his 29th ranking event.[2]

Prize fund

The breakdown of prize money for this year is shown below:[3]

The "rolling 147 prize" for a maximum break stood at £25,000.

Main draw

Final

Qualifying

These matches were held between 1 and 2 August 2017 at the Preston Guild Hall in Preston, England. All matches were best of 7 frames.[4]

Notes
  1. 1234567Match was held over and played in India.
  2. 123456Wildcard

Century breaks

Qualifying stage centuries

Total: 18

Televised stage centuries

Total: 14

References

  1. "2017/18 World Snooker Calendar"(PDF). World Professional Billiards and Snooker Association. 14 July 2017. Retrieved 14 July 2017.
  2. "Indian Open: John Higgins beats Anthony McGill to take title". BBC Sport. 16 September 2017. Retrieved 5 February 2018.
  3. "Indicative Prize Money Rankings Schedule 2017/2018 Season"(PDF). worldsnooker.com. World Professional Billiards and Snooker Association. 14 July 2017. Retrieved 14 July 2017.
  4. "2017 Indian Open Qualifiers". snooker.org. 1 August 2017. Retrieved 1 August 2017.